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Grade: 11 

                        
Plz solve the ques. Calculate the % of ionic character in NaF if electronegativities of Na and F are 0.9 and 4.0 respectively
3 years ago

Answers : (1)

Arun
24742 Points 
							
Percentage ionic character in NaF
= [E.N.(Na) - E.N(F)]* 100/E.N.(Na)
= (4- 0.9) * 100/4
= 3.1 *25
= 77.5 %
3 years ago
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