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Plz solve the ques. Calculate the % of ionic character in NaF if electronegativities of Na and F are 0.9 and 4.0 respectively Plz solve the ques. Calculate the % of ionic character in NaF if electronegativities of Na and F are 0.9 and 4.0 respectively
Percentage ionic character in NaF= [E.N.(Na) - E.N(F)]* 100/E.N.(Na)= (4- 0.9) * 100/4= 3.1 *25= 77.5 %
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