Please please sir explain this question to me.I am confused why option a is not possible. It don't have any plane of symmetry and H attached at - CH 3 have 4 different group .So why option a is not possible?

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Pooja · Answer

Dear Student
In option A if H2 is added there is a possibility of the H atoms to get added below the plane and making methyl group on double bond to go above the plane. the alkane so made will have a plane of symmetry which will make it optically inactive.

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Please please sir explain this question to me.I am confused why option a is not possible. It don't have any plane of symmetry and H attached at - CH 3 have 4 different group .So why option a is not possible?

Please please sir explain this question to me.I am confused why option a is not possible. It don't have any plane of symmetry and H attached at - CH₃ have 4 different group .So why option a is not possible?

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Please please sir explain this question to me.I am confused why option a is not possible. It don't have any plane of symmetry and H attached at - CH 3 have 4 different group .So why option a is not possible?

Please please sir explain this question to me.I am confused why option a is not possible. It don't have any plane of symmetry and H attached at - CH3 have 4 different group .So why option a is not possible?

1 Answers

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Please please sir explain this question to me.I am confused why option a is not possible. It don't have any plane of symmetry and H attached at - CH₃ have 4 different group .So why option a is not possible?