Grade 11Organic Chemistry
No of oxalic acid molecules in 100 ml of 0.02 N oxalic acid is
No of oxalic acid molecules in 100 ml of 0.02 N oxalic acid is
2 Answers
Arun
Normality=molarity×basicity for acids/acidity for bases
Here N=0.02 & as oxalic acid is a dibasic acid so it will have a badicity of 2.
M=0.02÷2=0.01
Molarity=no of moles × volume(lit)
M=0.01×0.1=0.001moles
As 1 mole= 6.603×10*23=6.6×10*23×0.001= 6.6×10*20
Khimraj
As Oxalic acid is dibasic, n-factor (Basicity) = 2
Now, Normality = No. of moles / n-factor / Vol in litres.
So, 0.02 = n x 2/0.1 i.e. n = 0.001
Thus no. of molecules = Avagadro no / No. of moles = 6.022 x 1020 molecules
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