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First order reaction the rate in 0.1 s. Thus the 20g reactant when reduce to 5g calculate time?

First order reaction the rate in 0.1 s. Thus the 20g reactant when reduce to 5g calculate time?

Grade:11

1 Answers

Ankit
104 Points
6 years ago
Given that Initial quantity, [R]o= 20gFinal quantity, [R] = 5g Rate constant, k = 1 x 10−1 s−1Formula of 1st order reaction,. . . . . .K=(2.303/t)(log[R]o/log[R]). . . . . . . . . . . . . . . . . . . Plug the values we get Value of log 20/5 = log 20 – log 5 = 1.3010-0.6990. . . . . . . .= (0.6020). . . . . . . . . . After applying formula k= (2.303/1*10-1)(0.6020). . . . . . . . . .=(23.03*0.6020) After calculation we get 13.864 sec . . . . . . .Hence, it will take 13.864 sec to reduce 20 g of this reactant to 5 g. . . . . . . . Thank u

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