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calculate the mass of NaCl (molecular mass = 5.85 mol) to be dissolved in 40 g of water to lower the freezing point by 2degree celsius, assuming that NaCl undergoes complete dissociation. [ Kf for water = 1.86 kg mol]
This is a colligative property based question.we know the formula for lowering of freezing point is :-i*K*m=del THere m is molality and K is the dissociation constant. On applying the formula we get the mass of NaCl to be 1.25g.
This is a colligative property based question.we know the formula for lowering of freezing point is :-
i*K*m=del T
Here m is molality and K is the dissociation constant. On applying the formula we get the mass of NaCl to be 1.25g.
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