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b) 3 g of dihydrogen react with 29.0 g of dioxygen to yield water as follows. O 2 (g) + 2H 2 (g) ----------------- ? 2H 2 O (g) 1. Which is limiting reactant? 2. Calculate the maximum amount of H 2 O that can be formed. 3. Calculate the amount of one of the reactants which remains unreacted.
@ shaik here the equation is balanced , so, we need to calculate no of moles frst , h2 = 3/2 = 1.5 moles o2 = 29/32 = 0.90 moles then just divide the no of moles with the coefficient of balanced equation h2 = 1.5 / 2 = 0.75 o2 = 0.90/ 1= 0.90 so, here H2 will be the limiting reagent , HOPE IT CLEARS
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