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`        A 7 ,3,2kg block placed one over other in this order with 2 at the top coefficent of friction b/w 2kg &3kg is 0.2and b/w 7kg and 3kg is 0.3 when 10 n force app. On 2kg block find acceleration of each assume fric b/w ground and 7kg is 0`
2 years ago

Vikas TU
10337 Points
```							Since the applied force is 10 N we will first find the acceleration of the whole system So the system will have an acceleration of 5/6. We know that friction actually opposes relative motion so we will have to go into the referece frame of the blocks to understand the motion.Using that we will get the accelerations to be 13/6 ,19/18 ,5/14 for 2 , 3 and 7 kg respectively.
```
one year ago
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• 70 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions