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Grade: 11
        35 ml sample of hydrogen peroxide gives off 500ml of o2 at 27°C and 1atm pressure. volume strength of h2o2 sample wii be
10 months ago

Answers : (2)

Arun
14889 Points
							
Dear Avinash
 
Use PV=nRT and solve for n = PV/RT to get the number of moles of O2 given off 
and substitute 
n=PV/RT 
Substitute 
P= 1 atm 
V=.500 L (notice you need to convert to L to match the units in R) 
R=0.082 L atm/ (mol K) 
T= 300 K 

a. Solve for n to get moles of O2 released. n=.0203 

b. You can get the volume of O2 relesed at stp from 22.4 L/moles of O2 at STP = 0.4553 

c. For every mole of H2O2 you get one mole of O2 released, so that tells you 

moles H2O2 in the solution = 00203 = 15.48 g H2O2 in the solution 

If you assume the density of H2O2 is the same as water, then you have 15.5 mL of H2O2 in the solution and the V/V % is 15.5x100/35 = 44% You could also say the w/v % is the same number. It is unclear which you are looking for.
 
 
Regards
Arun (askIITians forum expert)
10 months ago
Dylan
13 Points
							
See, first find volume if oxygen that canbe produced at stp...
Therfore, v1/t1=v2/t2(modi 's law)
V2=500*273/300(by substituting values in the equation)
=455ml
35ml can produce 455ml of oxygen at stp,
Therfore(unitary method) 1000ml can produce 1000*455/35
=13000ml=13l
2 months ago
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