d dipole moment of d real molecule of chloroethane compared to that of d resonance contributor CH2=CH-Cl will be a)higher b)lower c)identical. & why? 2)which compounds give +ve iodoform test, what is its mechanism. plz explain mechanism of stereochemistry in case of alkenes,alkyl hallides.

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SAGAR SINGH - IIT DELHI · Answer

Dear student,

It is pretty obvoius that the dipole moment of chloroethane will be less than the resonance contributor..

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d dipole moment of d real molecule of chloroethane compared to that of d resonance contributor CH2=CH-Cl will be a)higher b)lower c)identical. & why? 2)which compounds give +ve iodoform test, what is its mechanism. plz explain mechanism of stereochemistry in case of alkenes,alkyl hallides.

d dipole moment of d real molecule of chloroethane compared to that of d resonance contributor CH2=CH-Cl will be a)higher b)lower c)identical. & why? 2)which compounds give +ve iodoform test, what is its mechanism. plz explain mechanism of stereochemistry in case of alkenes,alkyl hallides.

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d dipole moment of d real molecule of chloroethane compared to that of d resonance contributor CH2=CH-Cl will be a)higher b)lower c)identical. & why? 2)which compounds give +ve iodoform test, what is its mechanism. plz explain mechanism of stereochemistry in case of alkenes,alkyl hallides.

d dipole moment of d real molecule of chloroethane compared to that of d resonance contributor CH2=CH-Cl will be a)higher b)lower c)identical. & why? 2)which compounds give +ve iodoform test, what is its mechanism. plz explain mechanism of stereochemistry in case of alkenes,alkyl hallides.

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