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The compound C4H10O4 reacts with acetic anhydride to give a derivative with the formula C12H18O8. Then find the number of OH group present in original substance.
there are 4 -OH groups present
Mr.Raju can u pls explain..
let us take an example,
(CH3CO)2O + CH3CH2OH → CH3CO2CH2CH3 + CH3COOH
so we see when it is reacted with acetic anhydride the OH group is replaced with -CO2CH3CH2
so there must be 4 -OH groups in C4H10O4 please approve both the reply.
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