The empirical formula of the compound is CH2O . Its molecular weight is 180.The molecular formula of the compound is

Hi,

the wt of emperical = 12+2+ 16= 30

molecular formula = n ( emperical formula)

the way to calculate n:

n =   molecular wt of the compound /  wt of emperical formula

here we hav  n = 180/30 = 6

hence the molecular formula = 6 ( emperical formula)

i.e  6(CH₂O) = C₆H₁₂O₆

good luck & enjoy ur preparation

atomic weight of C=12 ,H=1,O=16 ,

mol. wt. of CH₂O is 30

given mol. wt. of compound (nCH₂O) is 180,

n=180/30=6

so, compound is C₆H₁₂O₆

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Ramesh  
IIT Kgp - 05 batch

hi,

 empirical wt . of compound = 12 + 2 + 16

                                         = 30

 mol. wt is 180 

thw ratio between the two wt. is called n

          n = 180/ 30

             =6 

so, the mol. formula of compoundwill be 

                                           =  ( CH_{2 ^{o )} 6}

                                            = C₆ H₁₂ O₆