The empirical formula of the compound is CH_{2^{O . Its molecular weight is 180.The molecular formula of the compound is}}

Hi,

the wt of emperical = 12+2+ 16= 30

molecular formula = n ( emperical formula)

the way to calculate n:

n =   molecular wt of the compound /  wt of emperical formula

here we hav  n = 180/30 = 6

hence the molecular formula = 6 ( emperical formula)

i.e  6(CH₂O) = C₆H₁₂O₆

good luck & enjoy ur preparation

atomic weight of C=12 ,H=1,O=16 ,

mol. wt. of CH₂O is 30

given mol. wt. of compound (nCH₂O) is 180,

n=180/30=6

so, compound is C₆H₁₂O₆

--

Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult
to understand - post it here and we will get you the answer and detailed solution very quickly.We are all
IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Ramesh  
IIT Kgp - 05 batch

hi,

 empirical wt . of compound = 12 + 2 + 16

                                         = 30

 mol. wt is 180 

thw ratio between the two wt. is called n

          n = 180/ 30

             =6 

so, the mol. formula of compoundwill be 

                                           =  ( CH_{2 ^{o )} 6}

                                            = C₆ H₁₂ O₆