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Grade: 11
        0.25M solution of pyridinium chloride was found to have a pH of 2.699. What is Kb for pyridine?
2 years ago

Answers : (4)

DR STRANGE
212 Points
							
            [Py-1] + [H20] ---->  [PyOH]  + [H+]
            C(1-a)                       Ca          Ca
 [PyOH][H+
------------------    =  Kh
 [Py-1][H20]
 
=> Kh = Kw / Kb 
[H+] = Ca = \sqrt{}(Kh.C)
 
So we get Ph =  – ½ [ log C + log Kw – log Kb ]
So Pkb = – log C + Pkw – 2(Ph) 
 
Pkb = 9.2041
Kb = 6.25 x 10-10
 
 – Arnesh Nagdeve, 
IIT Bombay
            [Py-1] + [H20] ---->  [PyOH]  + [H+]
            C(1-a)                       Ca          Ca
 [PyOH][H+
------------------    =  Kh
 [Py-1][H20]
 
=> Kh = Kw / Kb 
[H+] = Ca = \sqrt{}(Kh.C)
 
So we get Ph =  – ½ [ log C + log Kw – log Kb ]
So Pkb = – log C + Pkw – 2(Ph) 
 
Pkb = 9.2041
Kb = 6.25 x 10-10
 
 – Arnesh Nagdeve, 
IIT Bombay
2 years ago
DR STRANGE
212 Points
							
Plz approve if you are satisfied :)....................................................................................................................
2 years ago
Ashutosh Mohan Sharma
askIITians Faculty
180 Points
							509-2316_Screen Shot 2016-11-19 at 1.11.14 PM.png
						
2 years ago
Ashutosh Mohan Sharma
askIITians Faculty
180 Points
							509-2316_Screen Shot 2016-11-19 at 1.11.14 PM.png
						
2 years ago
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