Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
integral of root tanx divided by only secx
multiply up and down by secxtanx then subsitute secx=tafter that put root(t)=mand then the eq. becomes,,..2.int.[1/(1+m^4)]which can easily be found.regards
hey man you can find int.[1/1+m^4]...put 1=1/2[1-m^2/1+m^4 + 1+m^2/1+m^4]..!!!its an algebric twin
how u r getting 2integral of 1 divided by 1 plus mpower4
multiply both num and deno with tanx.secx
then sub secx=t
then divide the quad in denominator to get (1-1\t^2)in the root
then solve by taking √quad as m and find
multiply secx tanx subsitute secx=tand then the eq. becomes,,..2.int.[1/(1+m^4)]which can easily be found
multiply secx tanx
subsitute secx=tand then the eq. becomes,,..2.int.[1/(1+m^4)]which can easily be found
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !