Join now for JEE/NEET and also prepare for Boards Become an IITian/Doctor with FREE iCAT Scholarship | Date: 25 April, 2021 Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
integral of root tanx divided by only secx
multiply up and down by secxtanx then subsitute secx=tafter that put root(t)=mand then the eq. becomes,,..2.int.[1/(1+m^4)]which can easily be found.regards
hey man you can find int.[1/1+m^4]...put 1=1/2[1-m^2/1+m^4 + 1+m^2/1+m^4]..!!!its an algebric twin
how u r getting 2integral of 1 divided by 1 plus mpower4
multiply both num and deno with tanx.secx
then sub secx=t
then divide the quad in denominator to get (1-1\t^2)in the root
then solve by taking √quad as m and find
multiply secx tanx subsitute secx=tand then the eq. becomes,,..2.int.[1/(1+m^4)]which can easily be found
multiply secx tanx
subsitute secx=tand then the eq. becomes,,..2.int.[1/(1+m^4)]which can easily be found
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !