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integral of root tanx divided by only secx

integral of root tanx divided by only secx

Grade:

5 Answers

Akash Kumar Dutta
98 Points
7 years ago

multiply up and down by secxtanx then subsitute secx=t
after that put root(t)=m
and then the eq. becomes,,..
2.int.[1/(1+m^4)]
which can easily be found.
regards

Akash Kumar Dutta
98 Points
7 years ago

hey man you can find int.[1/1+m^4]...
put 1=1/2[1-m^2/1+m^4  + 1+m^2/1+m^4]..!!!
its an algebric twin

satheesh gumudavelly
25 Points
7 years ago

how u r getting 2integral of 1 divided by 1 plus mpower4

Abhishekh kumar sharma
34 Points
7 years ago

multiply both num and deno with tanx.secx

then sub    secx=t

then divide the quad in denominator to get (1-1\t^2)in the root

then solve by taking √quad as m and find

Pratibha Rani
39 Points
7 years ago

 

multiply secx tanx 

subsitute secx=t

and then the eq. becomes,,..
2.int.[1/(1+m^4)]
which can easily be found



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