The wavelength of photons in two cases are 4000 A and 3600 A respectively what is difference in stopping potential for these two? (Give solution using formula)

Question

Eshan · Answer

Dear student,

Stopping potential for an incoming photon is equal to the energy of it per unit charge.

Hence stopping potential of $4000A^{\circ}$ photon is $\dfrac{hc}{e\lambda}=3.1V$

Hence stopping potential of $3600A^{\circ}$ photon is $\dfrac{hc}{e\lambda}=3.44V$
Hence the required difference=0.34V

ANJALI KUMARI · Answer

In 1st case : stopping potential=12400/4000=3.1ev. In 2nd case : stopping potential=12400/3600=3.44ev Difference=3.44- 2.06=0.34ev

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

The wavelength of photons in two cases are 4000 A and 3600 A respectively what is difference in stopping potential for these two? (Give solution using formula)

The wavelength of photons in two cases are 4000 A and 3600 A respectively what is difference in stopping potential for these two? (Give solution using formula)

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Modern Physics

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

The wavelength of photons in two cases are 4000 A and 3600 A respectively what is difference in stopping potential for these two? (Give solution using formula)

The wavelength of photons in two cases are 4000 A and 3600 A respectively what is difference in stopping potential for these two? (Give solution using formula)

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Modern Physics

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship