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The wavelength of photons in two cases are 4000 A and 3600 A respectively what is difference in stopping potential for these two? (Give solution using formula)

The wavelength of photons in two cases are 4000 A and 3600 A respectively what is difference in stopping potential for these two? (Give solution using formula)

Grade:11

2 Answers

Eshan
askIITians Faculty 2095 Points
3 years ago
Dear student,

Stopping potential for an incoming photon is equal to the energy of it per unit charge.

Hence stopping potential of4000A^{\circ}photon is\dfrac{hc}{e\lambda}=3.1V


Hence stopping potential of3600A^{\circ} photon is\dfrac{hc}{e\lambda}=3.44V
Hence the required difference=0.34V
ANJALI KUMARI
15 Points
2 years ago
In 1st case : stopping potential=12400/4000=3.1ev.                                    In 2nd case : stopping potential=12400/3600=3.44ev                                   Difference=3.44- 2.06=0.34ev

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