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We know that, de-Broglie wavelength λ = h/mv.
where the speed (r.m.s) of a gas particle at the given temperature (T) is given as,
½ mv2 = 3/2 KT
or, v = √ 3kT/m
Here K is Boltzmann’s constant, m is mass of the gas particle and T is the temperature of gas in K.
So, mv = √3mKT
or, λ = h/mv = h/√3mKT
Thus, λH/λHe = √ mHeTHe/mHeTH = √ (4 amu) (273+127º)K / (2 amu) (273+27º)K = √8/3
Regards
Arun (askIITians forum expert)
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