Guest

the position of a 2.00 kg metal ball being whirled on a chain as a function of time is: r(t) = 1.00m cos(pie t/(10 s))i + (1.00m (1+sin( pie t/(10 s)))j. find the net force on the ball a) at t= 0.500s and b) at t= 1.200s suooose the chain broke a t= 1.500 seconds . with what veocity would the ball fly off? with what momentium would the ball fly suppose after flying off the chain the ball had a force acting on it untill it collided with an 8.00 kg clay statue to which it stuck. what would be the momentium of the combined object, ball + clay statue, after collision?. what would be the velocity suppose the ball instead of colliding with a clay statue bounced off a heavy steel wall in a perfectly elastic collision so that the velocity after the collision was negative of its velocity before collidion. how much momenium would the ball impact to the wall? if the collision lasted 0.100 miliseconds, what was the the average force of the wall force of the wall on the ball during the collision

  1. the position of a 2.00 kg metal ball being whirled on a chain as a function of time is: r(t) = 1.00m cos(pie t/(10 s))i + (1.00m (1+sin( pie t/(10 s)))j. find the net force on the ball a) at t= 0.500s and b) at t= 1.200s
  2. suooose the chain broke a t= 1.500 seconds . with what veocity would the ball fly off? with what momentium would the ball fly
 
  1. suppose after flying off the chain the ball had a force acting on it untill it collided with an 8.00 kg clay statue to which it stuck. what would be the momentium of the combined object, ball + clay statue, after collision?. what would be the velocity
  2. suppose the ball instead of colliding with a clay statue bounced off a heavy steel wall in a perfectly elastic collision so that the velocity after the collision was negative of its velocity before collidion. how much momenium would the ball impact to the wall? if the collision lasted 0.100 miliseconds, what was the the average force of the wall force of the wall on the ball during the collision

Grade:12th pass

0 Answers

No Answer Yet!

ASK QUESTION

Get your questions answered by the expert for free