In mathematical representation of bohr's energy,En = KE + PE
En = 1/2 mv2 + (– KZe2 / rn)
here, can you please explain me how can we arrive at the above mentioned value of potential energy??
En = KE + PE
En = 1/2 mv2 + (– KZe2 / rn)
here, can you please explain me how can we arrive at the above mentioned value of potential energy??





between them. Charge of the electron is
and that of nucleus of atomic number
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