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How accurately can the position of a proton be determined without giving it more than 1.00 keV of kinetic energy?
v that the proton has after measurement. Hence KE = p2/2mp = 1 keV gives p ≈ 7.31 × 10-22 N s, which can be taken as ∆px. Hence ∆x = ħ/2(7.31 × 10-22) = 7.22 × 10-14 m.
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