Modern Physics> A satellite revolves in a circular orbit ...

A satellite revolves in a circular orbit at a height of 200km from the surface of Earth. If the period of revolution of satellite is 90 minutes, G=6.6610^-11 and mean radius is 610^6 m , calculate the average density of Earth

Abir , 7 Years ago

Grade 11

1 Answers

Khimraj

Time period of revolution of satellite T = 2π(r³/G*m_E)^1/2

So T² = 4π²(r³/G*m_E)

(G*m_E)/r³ = 4π²/T²

So (4π/3)G*ρ_E = 4π²/T²

Then ρ_E= 3π/(T²*G) = 3π/[(90*60)² * 6.66*10^-11]

SO ρ_E= 4853 Kg/m³

Hope it clears. If still you have doubt you can ask me.

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Last Activity: 7 Years ago

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Modern Physics> A satellite revolves in a circular orbit ...

A satellite revolves in a circular orbit at a height of 200km from the surface of Earth. If the period of revolution of satellite is 90 minutes, G=6.66*10^-11 and mean radius is 6*10^6 m , calculate the average density of Earth

Abir , 7 Years ago

Khimraj

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