A satellite moving in a circular path of radius r around earth has a time period T .if it's radius slightly increases by 4% then percentage change in its time period is

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Arun · Answer

Dear student According to Kepler's law- T&sup2; = kr&sup3; 2T dT/dr = 3 k r&sup2; = 3 T&sup2;/r dT/dr = 3/2 T/r.. Hence dT = (3T/2r)* r Now put the value of r = 0.04 r and find answer Regards Arun (askIITians forum expert)

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A satellite moving in a circular path of radius r around earth has a time period T .if it's radius slightly increases by 4% then percentage change in its time period is

A satellite moving in a circular path of radius r around earth has a time period T .if it's radius slightly increases by 4% then percentage change in its time period is

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A satellite moving in a circular path of radius r around earth has a time period T .if it's radius slightly increases by 4% then percentage change in its time period is

A satellite moving in a circular path of radius r around earth has a time period T .if it's radius slightly increases by 4% then percentage change in its time period is

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