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Grade: 11
        
A particle is projected with velocity U along x axis. The acceleration of the particle is proportional to the square of the distance from the origin a=kx², the distance at which the particle stops is
A)√3u/2k
B)(3u/2k)⅓
C)√2²/3k
D)(3u²/2k)⅓
one year ago

Answers : (1)

Arun
22998 Points
							
 
a = udu/dx = k*x^2 
udu = (k*x^2)dx
Integerating both sides,
 
k^2/2 = u*x^3/3
x = 3u/2k)^1/3
 
Hope it helps
 
Regards
Arun
one year ago
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