A particle is projected with velocity U along x axis. The acceleration of the particle is proportional to the square of the distance from the origin a=kx², the distance at which the particle stops isA)√3u/2kB)(3u/2k)⅓C)√2²/3kD)(3u²/2k)⅓
Sudhanva G V , 6 Years ago
Grade 11
1 Answers
Arun
Last Activity: 6 Years ago
a = udu/dx = k*x^2
udu = (k*x^2)dx
Integerating both sides,
k^2/2 = u*x^3/3 x = 3u/2k)^1/3
Hope it helps
Regards
Arun
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