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a garden hose with an internal diameter of 1.9 cm is connected to a(stationary) lawn sprinkler that consists merely of an enclosure with 24holes,each 0.13 cm in diameter. If the water in the hose has a speed of0.91 m/s,at what speed does it leave the sprinkler holes?
leta us consider the velocity of sprinkler is V2rate of mass flow will same at a time soincoming mass flow = outgoing mass flowso from the principle of continuityA1 V1 = A2V2since sprinkler is is N = 24 thenA1V1 = NA2V2pi* (D1 / 2)^2 *V1= pi*(D2/2)^2*V2V2 = D1^2*V1 / ND^2V2 = (1.9x10^-2)^2 *0.91 / 24*(0.13x10^-2)^2V2 = 8.1 m/s^2Thanks & Regards,Nirmal SinghAskiitians Faculty
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