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a garden hose with an internal diameter of 1.9 cm is connected to a (stationary) lawn sprinkler that consists merely of an enclosure with 24 holes,each 0.13 cm in diameter. If the water in the hose has a speed of 0.91 m/s,at what speed does it leave the sprinkler holes?
leta us consider the velocity of sprinkler is V2rate of mass flow will same at a time soincoming mass flow = outgoing mass flowso from the principle of continuityA1 V1 = A2V2since sprinkler is is N = 24 thenA1V1 = NA2V2pi* (D1 / 2)^2 *V1= pi*(D2/2)^2*V2V2 = D1^2*V1 / ND^2V2 = (1.9x10^-2)^2 *0.91 / 24*(0.13x10^-2)^2V2 = 8.1 m/s^2Thanks & Regards,Nirmal SinghAskiitians Faculty
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