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Grade: 11
        A certain element emits K base α X-ray of energy 3.69 keV. Use the data from the previous problem to identify the element. 
5 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
							E = 3.69 kev = 3690 eV
λ hc/E = 1242/3690 = 0.33658 nm
√c/λ = a(z - b); a = 5 * 10^7 √Hz , b = 1.37 (from previous problem)
√3 * 10^8/0.34 * 10^9 = 5 * 10^7 (Z – 1.37) ⇒ √8.82 * 10617 = 5 * 10^7 (Z – 1.37)
⇒ 9.39 * 10^8 = 5 * 10^7 (Z – 1.37) ⇒ 93.9 / 5 = Z – 1.37
⇒ Z = 20.15 = 20
∴ the element is calcium.

						
5 years ago
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