Grade 12th passModern Physics

A body is projected vertically with speed 10 and other at same time with same speed in downward direction from top of a tower.the magnitude of the accelaration of 1st body w.r.t 2nd body is what??

kritika taniya saharia

9 Years agoGrade 12th pass

2 Answers

Kuldeep Pal

9 Years ago

Zero:

As the motion is only in 1-Dimension so,There is no need for vecor sign. WE can assume as +se as vertical direction And -ve as downwars Direction.

a(relative)= a₁-a₂

according to our convention vertical motion is +ve and downward motion is -ve.

So. a₁=+g

a₂=-g

Hence ,

a(relative) = a₁-a₂

_=(+g)-(-g)

_=g-g

_=0.

Raman Mishra

9 Years ago

Dear Taniya, no need to fret. This is a very simple question used for confusing the students. Since the acceleration of both the bodies will be g downwards, therefore their relative acceleration will be zero.

Taking upward direction to be positive and ground as refrence, we have:

Acceleration of 1^st body = a₁ = -g

Acceleration of 2^nd body = a₂ = -g

$\therefore$ Acceleration of 1^st body wrt 2^nd is given by:

a₁₂ = a₁ – a₂ = -g – (-g) = 0

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A body is projected vertically with speed 10 and other at same time with same speed in downward direction from top of a tower.the magnitude of the accelaration of 1st body w.r.t 2nd body is what??

kritika taniya saharia

2 Answers

Kuldeep Pal

Raman Mishra

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