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A battery of emf 60V is connected across a parallel combination of a 8 ohm resistor and a thick wire of negligible resistance.If the current observed is 6A, what is the internal resistance of the battery? A battery of emf 60V is connected across a parallel combination of a 8 ohm resistor and a thick wire of negligible resistance.If the current observed is 6A, what is the internal resistance of the battery?
Calculate the internal resistance of the battery.Hence, the internal resistance is 12 ohm.
Internal resistance I=E/R+r6= 60/8+r48+6r=60-48 6r=12 ohmr=2 ohmHence, the internal resistance is 2 ohm.
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