# Assume that two deuteron nuclei in the core of fusion reactor at temperature T are moving towards each other, each with kinetic energy 1.5 kT, when the separation between them is large enough to neglect Coulomb potential energy. Also neglect any interaction from other particles in the core. The minimum temperature T required for them to reach a separation of 4 × 10-15 m is in the range

28 Points
14 years ago

Dear Ankita Shakya,

Ans:- The initial energy is totally linetic and the total energy is=2(1.5kT)=3kT and initially there is no coulombic P.E.

Then finally the total energy must be converted to the potential energy as the temp is minimum( assuming the final temp to be zero). Hece from energy equation we get

Kq²/r=initial KE

Solving we get,

T=(5.12×10^-14)/k(ans)

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Soumyajit Das IIT Kharagpur

28 Points
14 years ago

Dear STUDENT NAME,

In the previous solution the answer was wrong due to some calculation mistake please note the correct answer. The correct Temperature is T=(1.92×10^-14)/k Kelvin where k is a constant

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