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If uncertainty in momentum is twice the uncertainty in position of an electron then uncertainty in velocity is:
(A, B)Sol. B.E. of 4th state = 13.6 z^2/n^2 => 13.6 z^2/4^2 = 13.6 => z = 4 sample is Be3+ => energy of electron in 3rd state state = 1.5 × 42 = 24 eV therefore 25 eV photon will cause ionization.
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