Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is(a) 3.4eV(b) 6.8eV(c) -3.4 eV(c) -6.8 eV
Navjyot Kalra , 11 Years ago
Grade 10
1 Answers
Aditi Chauhan
Last Activity: 11 Years ago
(a)
K.E. = (13.6eV)
Mechanical energy = (13.6 eV)
\K.E. in 2nd orbital for hydrogen
= - Mechanical energy
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