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The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is (a) 3.4eV (b) 6.8eV (c) -3.4 eV (c) -6.8 eV



The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is


        (a)    3.4eV       


(b)    6.8eV


        (c)    -3.4 eV


        (c)    -6.8 eV


Grade:10

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
7 years ago

        (a)

K.E. =  (13.6eV) 

Mechanical energy = (13.6 eV) 

\      K.E. in 2nd orbital for hydrogen

= - Mechanical energy

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