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A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of width=36atoms (of mass 62.92960 u).

Narayanarao laveti , 11 Years ago
Grade 12
anser 2 Answers
naninagaraju sivacharan lakshmi narsing

Last Activity: 11 Years ago

hai laveti you come in dorm  and ask the question answer

thanks

orey laveti iam nagesh

seethayya Barri

Last Activity: 11 Years ago

Mass of a copper coin, m’ = 3 g
Atomic mass of atom, m = 62.92960 u
The total number of  atoms in the coin
Where,
N
A = Avogadro’s number = 6.023 × 1023 atoms /g
Mass number = 63 g
nucleus has 29 protons and (63 − 29) 34 neutrons
∴Mass defect of this nucleus, Δm'' = 29 × m
H + 34 × m
n − m
Where,
Mass of a proton, m
H = 1.007825 u
Mass of a neutron, m
n = 1.008665 u
∴Δm'' = 29 × 1.007825 + 34 × 1.008665 − 62.9296
= 0.591935 u
Mass defect of all the atoms present in the coin, Δm = 0.591935 × 2.868 × 1022

= 1.69766958 × 1022 u
But 1 u = 931.5 MeV/c2

∴Δm = 1.69766958 × 1022 × 931.5 MeV/c2
Hence, the binding energy of the nuclei of the coin is given as:
E
b= Δmc2

= 1.69766958 × 1022 × 931.5 
= 1.581 × 1025 MeV
But 1 MeV = 1.6 × 10−13 J
E
b = 1.581 × 1025 × 1.6 × 10−13 

= 2.5296 × 1012 J
This much energy is required to separate all the neutrons and protons from the given coin.

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