veeravalli mohan
Last Activity: 12 Years ago
consider an electron revolving around nucleus in a circular orbit
here the circumference is equal to whole number multiple of wavelength of electron waves
so
2 pie r=n lamda
lamda=2 pie r/n
from diebrog;ie concept
lamda=h/mv
therefore
h/mv=2 pie r/n
m.v.r=n.h/2 pie
hence its integral multiple of h/2 pie
v is velocity of electron,
r is the radii
angular momentum is n.h/2 pie
hence