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an object os first sliding down an inclined plane of inclination of an angle theta with constant velocity . it is next projected up the same plane with an initial velocity u. calculate the distance upto which it will rise before coming to rest. what will happen to the object after it has come to rest. i am a 11th std student under CBSE curriculum. pls help mw i find this chapter tough.

an object os first sliding down an inclined plane of inclination of an angle theta with constant velocity .


it is next projected up the same plane with an initial velocity u. calculate the distance upto which it will rise before coming to rest.


what will happen to the  object after it has come to rest.


i am a 11th std student under CBSE curriculum. pls help mw i find this chapter tough.

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2 Answers

Aman Bansal
592 Points
11 years ago

Dear krishna,

This is a simple problem of projectile , use this formula to evaluate

range

Best Of luck

Plz Approve the answer...!!!!

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Aman Bansal

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Chetan Mandayam Nayakar
312 Points
10 years ago

constant velocity implies friction force=mgsin(theta)=k1*mgcos(theta),where k1 is coefficient of kinetic friction.                    So k1=tan(theta),

downward force=mg(sinθ+(k1)cos(theta))=2mgsinθ

Let the distance upto which it will rise before coming to rest=d, u2=2dgsinθ,d=u2/(2gsinθ),

after coming to rest, downward gravity=mgsin(theta)=(k1)mgcos(theta), maximum static friction=(k2)mgcos(theta), k2 is coefficient of static friction. Now,k1<k2, therefore the object will remain at rest

 

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