Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

an object os first sliding down an inclined plane of inclination of an angle theta with constant velocity . it is next projected up the same plane with an initial velocity u. calculate the distance upto which it will rise before coming to rest. what will happen to the object after it has come to rest. i am a 11th std student under CBSE curriculum. pls help mw i find this chapter tough.

an object os first sliding down an inclined plane of inclination of an angle theta with constant velocity .


it is next projected up the same plane with an initial velocity u. calculate the distance upto which it will rise before coming to rest.


what will happen to the  object after it has come to rest.


i am a 11th std student under CBSE curriculum. pls help mw i find this chapter tough.

Grade:

2 Answers

Aman Bansal
592 Points
9 years ago

Dear krishna,

This is a simple problem of projectile , use this formula to evaluate

range

Best Of luck

Plz Approve the answer...!!!!

Cracking IIT just got more exciting,It’s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and winexciting gifts by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple click here to download the toolbar….
So start the brain storming…. become a leader with Elite Expert League ASKIITIANS

Thanks

Aman Bansal

Askiitian Expert

Chetan Mandayam Nayakar
312 Points
9 years ago

constant velocity implies friction force=mgsin(theta)=k1*mgcos(theta),where k1 is coefficient of kinetic friction.                    So k1=tan(theta),

downward force=mg(sinθ+(k1)cos(theta))=2mgsinθ

Let the distance upto which it will rise before coming to rest=d, u2=2dgsinθ,d=u2/(2gsinθ),

after coming to rest, downward gravity=mgsin(theta)=(k1)mgcos(theta), maximum static friction=(k2)mgcos(theta), k2 is coefficient of static friction. Now,k1<k2, therefore the object will remain at rest

 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free