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the radius of a nucleus of mass no. 16 is 3 Fermi.Find the radius of the nucleus of mass no. 128?
Average radius if nucleus is given by:
R = R0A1/3 A:mass number R0 = 1.1x10-15m =1.1 fermi
so, R1/R2 = (A1/A2)1/3
given R1 = unknown , R2 = 3 fm , A1 = 128 , A2 = 16
So, R1 = 2*(128/16)1/3
R1 = 6 fermi
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A small mistake from above solution
its
So, R1 = 3*(128/16)1/3 R1 = 6 fermi
So, R1 = 3*(128/16)1/3
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