the radius of a nucleus of mass no. 16 is 3 Fermi.Find the radius of the nucleus of mass no. 128?

Average radius if nucleus is given by:

R = R₀A^1/3       A:mass number    R₀ = 1.1x10^-15m =1.1 fermi

so, R₁/R₂ = (A₁/A₂)^1/3

given R₁ = unknown ,    R₂ = 3 fm  , A₁ = 128  ,      A₂ = 16

So, R₁ = 2*(128/16)^1/3

R₁ = 6 fermi

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Naga Ramesh
IIT Kgp - 2005 batch

A small mistake from above solution

its

So, R₁ = 3*(128/16)^1/3

R₁ = 6 fermi

Dear Student,
Please find below the solution to your problem.

Average radius if nucleus is given by:
R = R0A^(1/3) A:mass number R0 = 1.1x10-15m =1.1 fermi
so, R1/R2 = (A1/A2)^1/3
given R1 = unknown , R2 = 3 fm , A1 = 128 , A2 = 16
So, R1 = 3*(128/16)^1/3
R1 = 6 fermi

Thanks and Regards