1) if the energy radius and velocity of an electron in the ground state of hydrogen atom are: E=-13.6ev, R 0.53A and V 2.2*10®6M/s respectively, calculate the energy radius and velocity for an electron of energy.n=3,n=5,n=10.2) If the excitation energy for two given levels of an atom is 10.2ev,calculate the wavelength of the emitted photon and the frequency. 3) If the energy level for n=1 is -13.6ev,find the energy level for n=3 and n=8 obtained. The excitation energy between the two levels in joules. 4) An atom excited to an energy level E2 falls to a ground state, calculate the frequency and the wavelength of the emitted photon. (h=6.63*10®-34js)E2=-1.51evE1=-13.6ev.
Blessing Aboyi , 8 Years ago
Grade 12th pass