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Why Range of particle will be maximum when dR/d alpha = 0?Pls show me it's proof with explanation.


2 years ago

Khimraj
3007 Points
							Range R = u2sin2$\alpha$/2gfor maximum range dR/d$\alpha$ = 0 {THis is the step forcalulating maxima of a function. You will read about this in mathematic differential calculus.}So 2u2cos2$\alpha$/2g = 0so $\alpha$ = 45

2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions