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WHAT IS THE FORCE F REQUIRED AT EQUILIBRIUM OF THE GATE?

Grade:12th pass

4 Answers

Venkat
273 Points
2 years ago
WHAT IS THE FORCE F REQUIRED AT EQUILIBRIUM OF THE GATE?
Venkat
273 Points
2 years ago
sorry the attachm
Venkat
273 Points
2 years ago
THE CORrect option is (b) = 0

$\\F_{horizontal}=0.5(9.81)(2)(2)=19.62kN$

It will act at
$1-\frac{2}{3}=\frac{1}{3}$
from the hinge

$\\F_{vertical}=\pi \times \frac{(1)^2}{2}(9.81)=\frac{9.81\pi}{2}kN$

It will act at     $\\\frac{4}{3\pi}$    from the hinge

Take moments anout hinge.
$\\19.62\times\frac{1}{3}-\frac{9.81\pi}{2}\times \frac{4}{3\pi}=F\times1 \\ \\\frac{19.62}{3}-\frac{19.62}{3}=F \\ \\F=0$
Aswanth
18 Points
2 years ago

THE CORrect option is (b) = 0

$\\F_{horizontal}=0.5(9.81)(2)(2)=19.62kN$

It will act at
$1-\frac{2}{3}=\frac{1}{3}$
from the hinge

$\\F_{vertical}=\pi \times \frac{(1)^2}{2}(9.81)=\frac{9.81\pi}{2}kN$

It will act at     $\\\frac{4}{3\pi}$    from the hinge

Take moments anout hinge.
$\\19.62\times\frac{1}{3}-\frac{9.81\pi}{2}\times \frac{4}{3\pi}=F\times1 \\ \\\frac{19.62}{3}-\frac{19.62}{3}=F \\ \\F=0$

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