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Weights of 1g,2g,.....,100g are suspended from 1cm,2cm,.....,100cm mark respectively. Where i t should be suppoted so, that the the system is in equlibrium??

Weights of 1g,2g,.....,100g are suspended from 1cm,2cm,.....,100cm mark respectively. Where it should be suppoted so, that the the system is in equlibrium??

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1 Answers

Kaustubh Nayyar
27 Points
7 years ago
the point must be the centre of mass
it can be calculated as
COM =  ( 1+22+3+ …......+1002 ) / ( 1+2+3+4+..........+100 ) 
         =  { (100)(101)(201) / 6 } / { (100)(101)/2}  
           = 201/3  = 67 cm for origin  if all the weights are at x axis
hence at 67cm from the origin or 66 cm from the first particle

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