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Grade: 11
        
Water is flowing through a horizontal pipe of non-uniform cross-section. the speed of water is 30 cm/s at a place where pressure is 10 cm (of water). calculate the speed of water at the other place where the pressure is half of that at the first place
2 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
3153 Points
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2 months ago
Khimraj
3008 Points
							
"We can solve this question by using Bernoulli's theorem. 
Which is,
 
Where,
P = pressure
 
v = velocity
h = height 
g = acceleration due to gravity
Since it is a horizontal pipe, the height (potential energy part becomes zero)
Now the equation can be changed as below,
but we know that, pressure (P) = ⍴hg
 
 
substituting the given values in the above equation,
 
 
 
 
 
 
Therefore, speed of water  "
2 months ago
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