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Water is flowing through a horizontal pipe of non-uniform cross-section. the speed of water is 30 cm/s at a place where pressure is 10 cm (of water). calculate the speed of water at the other place where the pressure is half of that at the first place

Water is flowing through a horizontal pipe of non-uniform cross-section. the speed of water is 30 cm/s at a place where pressure is 10 cm (of water). calculate the speed of water at the other place where the pressure is half of that at the first place

Grade:11

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
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Khimraj
3007 Points
4 years ago
"We can solve this question by using Bernoulli's theorem. 
Which is,
 
Where,
P = pressure
 
v = velocity
h = height 
g = acceleration due to gravity
Since it is a horizontal pipe, the height (potential energy part becomes zero)
Now the equation can be changed as below,
but we know that, pressure (P) = ⍴hg
 
 
substituting the given values in the above equation,
 
 
 
 
 
 
Therefore, speed of water  "

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