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`        Water is flowing through a horizontal pipe of non-uniform cross-section. the speed of water is 30 cm/s at a place where pressure is 10 cm (of water). calculate the speed of water at the other place where the pressure is half of that at the first place`
3 months ago

Saurabh Koranglekar
3163 Points
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3 months ago
Khimraj
3008 Points
```							"We can solve this question by using Bernoulli's theorem. Which is, Where,P = pressure v = velocityh = height g = acceleration due to gravitySince it is a horizontal pipe, the height (potential energy part becomes zero)Now the equation can be changed as below,but we know that, pressure (P) = ⍴hg  substituting the given values in the above equation,      Therefore, speed of water  "
```
3 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions