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two spheres A and B of masses M1 and M2 respectively collide.A is at any rest initially and B is moving with velocity V along x-axis after collision B has a velocity V/2 in a direction perpendicular to the original direction The Mass A moves after the collision in the direction
Here we will use 2- dimensional momentum conservationm1* 0 + m2* v = m2*0 + m1*VxaVxa = m2*v/m1 as B is moving in y direction only after collisionSimilarlym1*0 + m2*0 = m1* Vya + m2* v/2SoVya = - m2*v /2*m1HenceVya/Vxa = -1/2 = tanSo mass A will move tan --¹(-1/2) with positive x axis
Dear Student,Please find below the solution to your problem.We will use two dimensional moment conversation.let as assume the direction B move initially is positive x directionso we can write,m1×0+m2×V= m2×0+m1×VxA as B is moving y direction only a after collisionsoVxA = m2/m2 V towards positive directionand similarly m1 ×0+ m2×0 = m1 × VyA +m2×V/2VyA = - m2v/ 2m1VyA/VxA = - 1/2 = tanθmassA will move than tan^-1 (-0.5) = 26.5° with positive x axis.Thanks and Regards
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