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`        Two cities A and B are connected by a regular bus service with buses leaving in either direction every T seconds . The speed of each bus is uniform and equal to Vb  A cyclist cycles from A to B with a uniform speed Vc  (Vb >Vc ) . A bus goes fast the cyclist in T1 second in the direction A to B and every T2 second in the direction B to A .then (a) T1 = VbT /Vb +Vc  (b) T2 =VbT /Vb-Vc  (c) T1= VbT/Vb --Vc  (d) T2 = VbT/Vb --Vc Please explain this question without using relative velocity concept`
6 months ago

## Answers : (1)

Vikas TU
10040 Points
```							Hiiii Every bus is running in either direction from Ato B in every T second , So distnce from A to B would be = VbT an when bus is going from A to B , The relative velocity = Vb – Vc So, T1 = VbT / (Vb- Vc )so, C is th correct ans.
```
6 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions