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Two cities A and B are connected by a regular bus service with buses leaving in either direction every T seconds . The speed of each bus is uniform and equal to Vb A cyclist cycles from A to B with a uniform speed Vc (Vb >Vc ) . A bus goes fast the cyclist in T1 second in the direction A to B and every T2 second in the direction B to A .then
(a) T1 = VbT /Vb +Vc (b) T2 =VbT /Vb-Vc (c) T1= VbT/Vb --Vc (d) T2 = VbT/Vb --Vc
Please explain this question without using relative velocity concept

Ankit Singh , 6 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 6 Years ago

Hiiii 
Every bus is running in either direction from Ato B in every T second , 
So distnce from A to B would be = VbT 
an when bus is going from A to B , The relative velocity = Vb – Vc 
So, T1 = VbT / (Vb- Vc )
so, C is th correct ans.
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