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Grade: 11
        
Two cities A and B are connected by a regular bus service with buses leaving in either direction every T seconds . The speed of each bus is uniform and equal to V A cyclist cycles from A to B with a uniform speed Vc  (V>Vc ) . A bus goes fast the cyclist in Tsecond in the direction A to B and every T2 second in the direction B to A .then 
(a) T1 = VbT /V+V (b) T2 =VbT /Vb-V (c) T1= VbT/Vb --V (d) T2 = VbT/Vb --V
Please explain this question without using relative velocity concept
2 months ago

Answers : (1)

Vikas TU
8478 Points
							
Hiiii 
Every bus is running in either direction from Ato B in every T second , 
So distnce from A to B would be = VbT 
an when bus is going from A to B , The relative velocity = Vb – Vc 
So, T1 = VbT / (Vb- Vc )
so, C is th correct ans.
2 months ago
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Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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