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Grade: 12th pass
        
two blocks of mass 5 kg and 2 kg are connected by a spring of negligible mass and placed on a frictionless horizontol surface. an impulse gives a velociy of 7 m/s to the heavier block in the direction of the lighter block.the velociy of center of mass
2 years ago

Answers : (1)

Pushkar Prateek
23 Points
							
Heavier block receives impulse(very large force acted in very short time duration) and the smaller block doesn’t gain velocity in this impulsive period.
Vcm = (M1 V1 + M2 V2) / M1 + M2
        = (5x7 + 2x0) / 7
        =  5 m/s.
2 years ago
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