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two blocks of mass 5 kg and 2 kg are connected by a spring of negligible mass and placed on a frictionless horizontol surface. an impulse gives a velociy of 7 m/s to the heavier block in the direction of the lighter block.the velociy of center of mass
Heavier block receives impulse(very large force acted in very short time duration) and the smaller block doesn’t gain velocity in this impulsive period.Vcm = (M1 V1 + M2 V2) / M1 + M2 = (5x7 + 2x0) / 7 = 5 m/s.
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