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two blocks of mass 5 kg and 2 kg are connected by a spring of negligible mass and placed on a frictionless horizontol surface. an impulse gives a velociy of 7 m/s to the heavier block in the direction of the lighter block.the velociy of center of mass

two blocks of mass 5 kg and 2 kg are connected by a spring of negligible mass and placed on a frictionless horizontol surface. an impulse gives a velociy of 7 m/s to the heavier block in the direction of the lighter block.the velociy of center of mass

Grade:12th pass

1 Answers

Pushkar Prateek
23 Points
7 years ago
Heavier block receives impulse(very large force acted in very short time duration) and the smaller block doesn’t gain velocity in this impulsive period.
Vcm = (M1 V1 + M2 V2) / M1 + M2
        = (5x7 + 2x0) / 7
        =  5 m/s.

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