badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Two balls are thrown simultaneously, A vertically upwards with a speed of 20m/s from the ground, and B vertically downwards from a height of 40m with same speed and along same line of motion. At what points do the balls meet?

3 years ago

Answers : (1)

Mayank Sharma
44 Points
							Let balls meet at a distance of xmeter from top of the tower at time t.for ball A u= -20m/s,  S= -x meter, a=-9.8m/s^2,using eqn  S = u*t+ 1/2a*t^2 -x= -20*t+1/2*(-9.8)*t^2 - eqn ifor ball B u= 20 m/s, S=(40-x)m, a=-9.8m/s^2using eqn S=u*t+1/2a*t^240-x=20*t+1/2*(-9.8)*t^2 - eqn iiputting -x from eqn i in eqn ii,40-20*t+1/2(-9.8)*t^2=20*t+1/2(-9.8)*t^240-20*t=20*t (linear eqn in t hence only one soln ie balls meet only once )40=40*t ,=> t=1sputting t=1s in eqn i we get-x=-20+1/2(-9.8)-x=-20-4.9-x=-24.9x=24.9mhence balls meet only once at t=1s, at a distance of 24.9m from the top of the tower. or at a height of 15.1m(40-24.9=15.1).Hope this helps :)
						
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details