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Two balls are projected upward simultaneously with speed 40m/s and 60m/s . Relative position of second ball w.r.t first ball at time t=5s is
At t=5s;Distance covered by first ball = 40*5 – ½ * 10 * 52 = 200 – 125 = 75mDistance covered by second ball= 60 * 5 – ½ * 10 * 52 = 300 – 125 = 175m Relative position of second ball wrt to first ball = 175-75 =100m
Range = velocity × time R1=40×5=200R2=60×5=300relative position is R2-R1 so 300-200=100 100 m is the correct answer....
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