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Grade: 11
        
Two balls are projected upward simultaneously with speed 40m/s and 60m/s . Relative position of second ball w.r.t first ball at time t=5s is
2 years ago

Answers : (1)

Hasan Naqvi
97 Points
							
At t=5s;
Distance covered by first ball = 40*5 – ½ * 10 * 52 = 200 – 125 = 75m
Distance covered by second ball= 60 * 5 – ½ * 10 * 52 = 300 – 125 = 175m
 
Relative position of second ball wrt to first ball = 175-75 =100m
2 years ago
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