MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Soumyadeep Grade: 11
        
Two balls are projected upward simultaneously with speed 40m/s and 60m/s . Relative position of second ball w.r.t first ball at time t=5s is
2 years ago

Answers : (1)

Hasan Naqvi
97 Points
										
At t=5s;
Distance covered by first ball = 40*5 – ½ * 10 * 52 = 200 – 125 = 75m
Distance covered by second ball= 60 * 5 – ½ * 10 * 52 = 300 – 125 = 175m
 
Relative position of second ball wrt to first ball = 175-75 =100m
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details