Mechanics> Two balls are projected upward simultaneo...

Two balls are projected upward simultaneously with speed 40m/s and 60m/s . Relative position of second ball w.r.t first ball at time t=5s is

Soumyadeep , 10 Years ago

Grade 11

2 Answers

Hasan Naqvi

At t=5s;

Distance covered by first ball = 40*5 – ½ * 10 * 5² = 200 – 125 = 75m

Distance covered by second ball= 60 * 5 – ½ * 10 * 5² = 300 – 125 = 175m

Relative position of second ball wrt to first ball = 175-75 =100m

Last Activity: 10 Years ago

shubham

Range = velocity × time

R1=40×5=200

R2=60×5=300

relative position is R2-R1

so 300-200=100

100 m is the correct answer....

Last Activity: 7 Years ago

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Mechanics> Two balls are projected upward simultaneo...

Two balls are projected upward simultaneously with speed 40m/s and 60m/s . Relative position of second ball w.r.t first ball at time t=5s is

Soumyadeep , 10 Years ago

Hasan Naqvi

shubham

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