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Two balls are projected from the same point in directions inclined at 60 and 30 to the horizontal. If they attain the same maximum height, the ratio of their velocities of projection is : A) 1 : 1 B) 1 : 2 C) 1 : p 3 D) p 3 : 1
Two balls are projected from the same point indirections inclined at 60 and 30 to thehorizontal. If they attain the same maximumheight, the ratio of their velocities of projectionis :A) 1 : 1 B) 1 : 2 C) 1 :p3 D)p3 : 1

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10 months ago

Saurabh Koranglekar
10341 Points
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10 months ago
Vikas TU
14149 Points
```							Dear student Given-θ1=30°θ2=60°# Formula-- Height-H = u^2.(sinθ)^2 / 2g- Range-R = u^2.sin2θ / g# Calculations-Let u1 and u2 be the initial velocities for angle 30° and angle 60°.a) When range is same,R1 = R2u1^2.sin60/g = u2^2.sin120/gu1^2×0.866 = u2^2×0.866u1 = u2u1/u2 = 1b) When heights are same,H1 = H2u1^2.(sin30)^2/2g = u2^2.(sin60)^2/2gu1^2×(0.5)^2 = u2^2×(0.866)^20.25×u1^2 = 0.75×u2^2u1^2 = 3×u2^2u1/u2 = √3
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10 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions