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`        Time period of a simple pendulum of length L is T1 and time period of a uniform rod of the same length is pivoted at one end an oscillating in a vertical plane is T2 . Amplitude of oscillation in both the cases is small. Then T1/T2 isA) 1/3½        B) 1C) (4/3)½      D)  (3/2)½`
one year ago

Arun
24497 Points
```							For T1 we have to use formula T 1 = √L/g as it is a simple pendulum.T 2 = √I/mgy as it is compound pendulum.T 1 = √L/gT 2 = √mL^2/3mgL= √2L/3T 1 / T 2 = √L/g ÷ √2L/3= √3/2.
```
one year ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions