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`        The velocity of a block of mass 6 kg as a function of time . V = 5t^2+3t+2 m/s /.The force associated with the block at time t= 2s is,`
one year ago

Arun
24497 Points
```							Dear Rahul F = maand a = dv/dt hence a = 10t + 3at t = 2 sec a = 23 Now F = 6*23 = 138 N RegardsArun(askIITians forum expert)
```
one year ago
K VIVEK HRUDAY
40 Points
```							v=5t2+3t+2
m=6KG
t=2Sec                              [d/dt(xn)=n*xn-1}
dv/dt=10t+3                        since dv/dt=accelereation
a=10t+3
given,t=2sec
m=6KG
by substituting t=2 in a
we get,a=23m/s2
m=6KG
F=ma
F=23×6
F=138N
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions