Grade 12Mechanics

The spring mass system shown in the figure is in equilibrium at rest. If the mass is pushed up by a distance mg/2k and then released, it`s instantaneous acceleration will be(1)g (2)2g(3)g/2(4)0

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Aishwarya

8 Years agoGrade 12

2 Answers

Mahesh Koilada

8 Years ago

At equilibrium, mg=kx => x=mg/k; (this is the extension in the spring at equilibrium)

It’s given that the extension is reduced by a distance = mg/2k => new extension in the spring = x-mg/2k = x/2;

Equation of motion at the instant the mass is released from x/2 position

mg-kx/2=ma =>mg-mg/2=ma=> a = g/2

All the best.

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The spring mass system shown in the figure is in equilibrium at rest. If the mass is pushed up by a distance mg/2k and then released, it`s instantaneous acceleration will be(1)g (2)2g(3)g/2(4)0

Aishwarya

2 Answers

Mahesh Koilada

Ashutosh kumar

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