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Grade 11Mechanics

The position of a particle moving in an xy plane is given by +[(6 m) – (7 m/s4)t4] . Calculate (a) when t = 2 s.

Simran Bhatia

11 Years agoGrade 11

1 Answer

Aditi Chauhan

11 Years ago

Given:
Position of particle,

(a) The is the position of a particle, given as:

(b) The velocity of the particle is given as:

Now we apply the property of differentiation given as:

Using the property of differentiation one can obtain the velocity vector as:

(c) The acceleration vector $\overrightarrow{a}$ of the particle is:
$\overrightarrow{a} = \frac{\overrightarrow{v}}{dt}$
Substitute the velocity vector in equation (1) to obtain the acceleration as:

At t = 2 s the acceleration vector is:

Therefore the acceleration vector of the particle at is .

Therefore the acceleration vector of the particle at t = 2s is

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