badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass

                        

The last soldier of an 80 m long marching troops runs from the end to its front,and then it runs back to the end with same speed.During this,marching troops covers a distance of 150 m.The distance covered by the soldier is , a). 310 b). 250 c). 230 d). 160

4 years ago

Answers : (1)

RANADIP TAH
34 Points
							Let v1 be the speed of last soldier & v2 be the speed of the marching troop. So relative velocity of soldier in forward motion is v1-v2 & relative vel. in backward motion is v1+v2.=> time(t) = distance / velocitySo, 150/v2 = 80/(v1-v2) + 80/(v1+v2)  = time(t)=> v2= 150/t=> putting v2= 150/ t in the above equation we get,=> v1t^2 -160v1t - 22500=0=> v1t^2 -250v1t + 90v1t -22500=0=> (v1t -250)(v1t +90)=0  Now we get ,Distance covered by soldier = v1 * t = 250m  (b)   [answer]
						
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details