Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        the gravitational field in a region is given by E=(10N/Kg)(i+2j+3k). find work done by an external agent to slowly shift a particle of mass 3kg from point O(0,0,0) TO A POINT P(3m, 4m, 5m).answer=-780J`
2 years ago

Deepak Kumar
31 Points
```							Mass of Particle = 3Kg.Gravitational Field = E = (10i +20j + 30k)N/Kg.Initial Position = O(0,0,0)m.Final Position = P(3,4,5)m.So Force on Particle = E*Mass of partical = (10i +20j +30k)*3= (30i +60j + 90k)N.Work done by external Force = – work done by Gravitational force.                                           = – (30i +60j + 90k)* ((3-0)i +(4-0)j +(5-0)K).                                           = – (90 + 240 + 450)Joule = – 780 Joule.
```
2 years ago
Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

Post Question