System shown in figure is in equilibrium .the magnitude of change in tension in the string just before and just after,when one of the spring is cut.mass of both the blocks is same and equal to m and spring constant of both springs is k

Question

Himanshu Rathour · Answer

Just after one of the spring is cut there will be no change in magnitude of tension in the string. Hence change in tension in string =0

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System shown in figure is in equilibrium .the magnitude of change in tension in the string just before and just after,when one of the spring is cut.mass of both the blocks is same and equal to m and spring constant of both springs is k

System shown in figure is in equilibrium .the magnitude of change in tension in the string just before and just after,when one of the spring is cut.mass of both the blocks is same and equal to m and spring constant of both springs is k

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System shown in figure is in equilibrium .the magnitude of change in tension in the string just before and just after,when one of the spring is cut.mass of both the blocks is same and equal to m and spring constant of both springs is k

System shown in figure is in equilibrium .the magnitude of change in tension in the string just before and just after,when one of the spring is cut.mass of both the blocks is same and equal to m and spring constant of both springs is k

1 Answers

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Other Related Questions on Mechanics

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